% Данные для задачи на метод наименьших квадратов

d9b=fliplr([0.1 0.172; 0.15 0.196;0.3 0.231; 0.5 0.263;1 0.319;1.5 0.355; 2 0.382; 3 0.423; 4 0.453; 6 0.496; 10 0.551; 12 0.568; 15 0.593]);

kd105b=fliplr([0.1 0.461; 0.2 0.494; 0.3 0.513; 0.5 0.537;1 0.571;1.5 0.590;2 0.605;3 0.624;4 0.639;5 0.649;6 0.658; 10 0.683; 15 0.702;30 0.732; 45 0.750;60 0.763; 75 0.772; 100 0.787; 150 0.803; 200 0.819]);

d226d=[ 0.501 0.1 ; 0.530 0.2 ; 0.547 0.3 ; 0.568 0.5 ; 0.598 1 ; 0.616 1.5 ; 0.646 3 ; 0.660 4 ; 0.678 6 ; 0.705 10 ; 0.726 15 ; 0.743 20 ; 0.769 30 ; 0.789 40 ; 0.809 50 ; 0.841 75 ; 0.865 100];

al307g= [1.767 0.1; 1.793 0.2; 1.809 0.3; 1.822 0.4; 1.842 0.6; 1.859 0.8; 1.873 1.0; 1.897 1.4; 1.913 1.7;...
        1.928 2;  1.943 2.3; 1.972 3; 2.017 4.2; 2.037 4.8; 2.074 6; 2.089 6.5; 2.123 7.7; 2.157 9; 2.185 10.1;...
        2.231 12; 2.255 13; 2.278 14; 2.344 17];

